| Classwise Concept with Examples | ||||||
|---|---|---|---|---|---|---|
| 6th | 7th | 8th | 9th | 10th | 11th | 12th |
| Content On This Page | ||
|---|---|---|
| Bar Graph & Double Bar Graph | Organising & Grouping Data | Histograms |
| Pie Chart | Probability and Related Terms | |
Chapter 5 Data Handling (Concepts)
Welcome to this advanced exploration of Data Handling, a chapter designed to significantly expand upon the foundational concepts introduced in Class 7. In today's information-rich world, the ability to effectively organize, visually represent, and interpret data is an indispensable skill. This section introduces more sophisticated techniques for managing larger datasets and delves into the mathematical framework for quantifying uncertainty: Probability. Our goal is to equip you with robust tools for making sense of numerical information encountered in diverse fields, from science and economics to everyday life.
We begin by revisiting the crucial process of organizing raw, collected data. While frequency distribution tables remain a fundamental tool, dealing with extensive datasets necessitates a more efficient approach. Thus, we introduce grouped frequency distribution tables. This method involves partitioning the entire range of data into distinct, non-overlapping categories called class intervals (e.g., $0-10$, $10-20$, $20-30$,...). Each interval has a lower class limit and an upper class limit. We then tally the number of data points (the frequency) that fall within each specific interval. This grouping allows for a more condensed and manageable summary of large amounts of information, revealing patterns that might be obscured in raw data.
Building on data organization, we enhance our repertoire of graphical representations. Moving beyond simple bar graphs (which are ideal for discrete data), we introduce the Histogram. A histogram is the graphical representation specifically designed for continuous data presented in a grouped frequency distribution. Visually similar to a bar graph, it has key distinctions:
- The bars represent the class intervals, and their widths correspond to the range of each interval.
- The height of each bar corresponds to the frequency of data points within that interval.
- Crucially, the bars in a histogram are drawn adjacent to each other, with no gaps between them (unless a particular class interval happens to have a frequency of zero), signifying the continuous nature of the data distribution.
Another powerful visualization tool introduced is the Pie Chart (also known as a circle graph). Pie charts excel at representing data where we want to show the proportion of different categories relative to the whole. The entire dataset is represented by a circle, and each category or component is depicted as a sector (a 'slice' of the pie). The defining characteristic is that the size of each sector, specifically its central angle, is directly proportional to the frequency or value of the component it represents. We learn the crucial calculation to determine the central angle for each sector: $$ \text{Central Angle} = \left( \frac{\text{Value of the Component}}{\text{Total Value}} \right) \times 360^\circ $$ Accurate construction requires careful use of a protractor to draw these angles from the center of the circle. Interpreting pie charts involves visually comparing the relative sizes of the sectors to understand the breakdown of the whole.
Finally, this chapter revisits and reinforces the fundamental concepts of Probability. Probability provides a mathematical way to measure the likelihood or chance of a specific outcome occurring in a situation involving uncertainty. We focus on random experiments – processes whose outcomes cannot be predicted with certainty before they happen, such as tossing a fair coin, rolling a standard die, or drawing a card from a well-shuffled deck. The probability of a specific event (a desired outcome or set of outcomes) is calculated using the fundamental formula: $$ P(\text{Event}) = \frac{\text{Number of Favourable Outcomes}}{\text{Total Number of Possible Outcomes}} $$ We explore related concepts like identifying all possible outcomes (the sample space) and understanding situations with equally likely outcomes. Calculating probabilities for simple events provides a foundation for understanding risk and chance in various contexts.
Bar Graph & Double Bar Graph
In our everyday lives, we often come across collections of facts or figures, whether it's the number of students in each class, the favourite colours of your friends, or the marks you scored in different subjects. This collection of facts is called data. Data can be numbers, descriptions, measurements, or observations. Handling data involves collecting, organising, presenting, and interpreting this information in a meaningful way.
To make data easy to understand and compare, we often represent it visually using graphs. Two common ways to represent categorical data are using bar graphs and double bar graphs.
Bar Graph
A bar graph is a way of representing data using rectangular bars of the same width. These bars can be drawn vertically or horizontally. The height (if vertical) or length (if horizontal) of each bar is proportional to the value or frequency it represents.
Bar graphs are useful for comparing the amounts or frequencies of different categories.
How to Draw a Bar Graph:
Follow these steps to construct a bar graph:
- Draw Axes: Draw two perpendicular lines intersecting at a point. The horizontal line is called the x-axis, and the vertical line is called the y-axis.
- Choose a Scale: Decide on a suitable scale for the axis that represents the values (usually the vertical axis). The scale determines the height of the bars. For example, you might decide that 1 unit length on the y-axis represents 5 students, 10 Rupees, or 100 kilograms, depending on the data. Choose a scale that allows you to represent all the data conveniently on the graph paper.
- Mark Categories: Mark the categories (like names of subjects, months, types of vehicles, etc.) along the axis that represents the categories (usually the x-axis). Leave uniform spaces between the bars.
- Draw Bars: For each category, draw a rectangular bar of uniform width. The height of the bar should correspond to the value of the data for that category, based on the chosen scale on the value axis.
- Label and Title: Label both the x-axis and the y-axis clearly, indicating what they represent (e.g., "Subject", "Number of Students"). Give a suitable title to the bar graph that describes the data being presented (e.g., "Student Preferences for Subjects").
Example 1. The following table shows the number of students in Class 8 of a school who prefer different subjects.
| Subject | Number of Students |
|---|---|
| Maths | 50 |
| Science | 45 |
| English | 30 |
| Social Science | 40 |
| Art | 25 |
Draw a bar graph to represent this data.
Answer:
Construction Steps:
1. Draw the x-axis and y-axis.
2. Label the x-axis as 'Subject' and the y-axis as 'Number of Students'.
3. Choose a scale for the y-axis. Since the number of students ranges from 25 to 50, a suitable scale would be 1 unit on the y-axis = 5 students or 10 students. Let's use 1 unit = 10 students.
4. Mark the subjects (Maths, Science, English, Social Science, Art) at equal intervals on the x-axis.
5. Draw bars for each subject with uniform width. The heights of the bars will be:
- Maths: 50 students / 10 students per unit = 5 units
- Science: 45 students / 10 students per unit = 4.5 units
- English: 30 students / 10 students per unit = 3 units
- Social Science: 40 students / 10 students per unit = 4 units
- Art: 25 students / 10 students per unit = 2.5 units
6. Label the axes and give the graph a title: "Student Preferences for Subjects in Class 8".
Double Bar Graph
A double bar graph is an extension of a bar graph. It is used when you need to compare two sets of data for the same categories. For example, you might want to compare the performance of students in two different exams in the same set of subjects, or compare sales figures of two different products over several months.
In a double bar graph, for each category, a pair of bars is drawn next to each other. These bars represent the values from the two different data sets. Different colours or shading patterns are used for the two bars in each pair to distinguish them.
How to Draw a Double Bar Graph:
The steps are similar to drawing a single bar graph, with slight modifications:
- Draw Axes: Draw two perpendicular axes (x-axis and y-axis).
- Choose a Scale: Decide on a suitable scale for the axis representing the values (usually y-axis), covering the range of values in both data sets.
- Mark Categories: Mark the categories along the axis representing the categories (usually x-axis). Leave space between groups of bars.
- Draw Pairs of Bars: For each category, draw two bars side-by-side, one for each set of data. Ensure the bars within each pair have the same width, and there is some space between different pairs of bars. The height of each bar should correspond to its value on the scale.
- Use Legend: Assign a different colour or shading pattern to the bars of each data set. Provide a legend (a small box showing the colour/pattern and the data set it represents) usually near the graph to help interpret the bars.
- Label and Title: Label both axes and give a clear title to the double bar graph.
Example 2. The marks obtained by a student in two terminal examinations (Term 1 and Term 2) in different subjects are given below.
| Subject | Term 1 Marks (Out of 50) | Term 2 Marks (Out of 50) |
|---|---|---|
| English | 35 | 40 |
| Hindi | 30 | 38 |
| Maths | 42 | 48 |
| Science | 38 | 43 |
| Social Science | 35 | 40 |
Draw a double bar graph to represent this data and answer the following questions:
(i) In which subject has the student improved the most?
(ii) In which subject has the student's performance deteriorated?
Answer:
Construction Steps:
1. Draw the x-axis and y-axis.
2. Label the x-axis as 'Subject' and the y-axis as 'Marks Obtained'.
3. Choose a scale for the y-axis. Marks range from 30 to 48. A scale of 1 unit = 5 marks is suitable.
4. Mark the subjects (English, Hindi, Maths, Science, Social Science) at equal intervals on the x-axis.
5. For each subject, draw two adjacent bars. Let one bar represent Term 1 marks and the other represent Term 2 marks. Use different colours, e.g., blue for Term 1 and green for Term 2.
Heights of the bars based on the scale (1 unit = 5 marks):
| Subject | Term 1 (Units) | Term 2 (Units) |
|---|---|---|
| English | $35/5 = 7$ | $40/5 = 8$ |
| Hindi | $30/5 = 6$ | $38/5 = 7.6$ |
| Maths | $42/5 = 8.4$ | $48/5 = 9.6$ |
| Science | $38/5 = 7.6$ | $43/5 = 8.6$ |
| Social Science | $35/5 = 7$ | $40/5 = 8$ |
6. Draw the bars according to these heights. Provide a legend indicating blue for Term 1 and green for Term 2. Label axes and title the graph "Student Performance in Two Terminal Examinations".
Interpretation and Answers:
We can analyse the data from the table or the double bar graph to answer the questions.
(i) In which subject has the student improved the most? Improvement in marks = Term 2 Marks - Term 1 Marks.
- English: $40 - 35 = 5$ marks
- Hindi: $38 - 30 = 8$ marks
- Maths: $48 - 42 = 6$ marks
- Science: $43 - 38 = 5$ marks
- Social Science: $40 - 35 = 5$ marks
The largest increase in marks is 8, which occurred in Hindi. So, the student has improved the most in Hindi.
(ii) In which subject has the student's performance deteriorated? Deterioration means a decrease in marks from Term 1 to Term 2. We look for cases where Term 2 Marks < Term 1 Marks.
- English: $40 > 35$ (Improved)
- Hindi: $38 > 30$ (Improved)
- Maths: $48 > 42$ (Improved)
- Science: $43 > 38$ (Improved)
- Social Science: $40 > 35$ (Improved)
In this case, the marks have increased in all subjects. Therefore, the student's performance has not deteriorated in any subject.
Organising & Grouping Data
When we collect raw data, it's often scattered and not easy to make sense of immediately. For example, a list of marks of 50 students in a test, just as numbers written one after another, doesn't quickly tell you the highest score, the lowest score, or how many students scored within a certain range.
Organising data means arranging it in a systematic way to make it understandable and useful for analysis and interpretation. One of the fundamental ways to organise data is by using frequency distribution.
Raw Data
The data collected in its original form, before any organisation or processing, is called raw data.
Example: The marks obtained by 20 students in a class test (out of 10 marks) might be recorded as follows:
| 7 | 5 | 8 | 6 | 9 | 7 | 5 | 8 | 6 | 7 |
| 9 | 5 | 6 | 8 | 7 | 9 | 6 | 5 | 8 | 7 |
Looking at this raw data, it's difficult to quickly answer questions like "How many students scored exactly 7 marks?" or "Which mark was scored by the highest number of students?".
Frequency Distribution Table
To make raw data more organised and easily interpretable, we can arrange it in a frequency distribution table. This table shows each distinct value of the data and the number of times it appears. The number of times a particular value occurs in the data is called its frequency.
Steps to create a frequency distribution table for ungrouped data:
- List all the distinct values that appear in the raw data in ascending or descending order in one column.
- For each distinct value, go through the raw data and mark a tally mark ($|$) for every occurrence of that value. To make counting easier, make blocks of five tally marks, where the fifth mark ($\bcancel{||||}$) crosses the previous four.
- Count the number of tally marks for each distinct value. This count is the frequency of that value. Write the frequency in a separate column.
- Add up all the frequencies. The sum of frequencies should be equal to the total number of data points in the raw data. This helps in checking if all data points have been counted correctly.
Example 1. Organise the marks obtained by 20 students (from the raw data example above) into a frequency distribution table.
Raw Data:
| 7 | 5 | 8 | 6 | 9 | 7 | 5 | 8 | 6 | 7 |
| 9 | 5 | 6 | 8 | 7 | 9 | 6 | 5 | 8 | 7 |
Answer:
Given raw data are marks out of 10 for 20 students.
The distinct marks obtained are 5, 6, 7, 8, and 9.
Let's count the frequency of each mark using tally marks:
- Mark 5: Appears 4 times (5, 5, 5, 5) -> $||||$
- Mark 6: Appears 4 times (6, 6, 6, 6) -> $||||$
- Mark 7: Appears 4 times (7, 7, 7, 7) -> $||||$
- Mark 8: Appears 4 times (8, 8, 8, 8) -> $||||$
- Mark 9: Appears 4 times (9, 9, 9, 9) -> $||||$
Now, construct the frequency distribution table:
| Marks | Tally Marks | Frequency (Number of Students) |
|---|---|---|
| 5 | $||||$ | 4 |
| 6 | $||||$ | 4 |
| 7 | $||||$ | 4 |
| 8 | $||||$ | 4 |
| 9 | $||||$ | 4 |
| Total | $4 + 4 + 4 + 4 + 4 = 20$ |
The total frequency is 20, which matches the total number of students. From this table, we can easily see that each mark from 5 to 9 was obtained by 4 students.
Grouping Data into Class Intervals
When the number of data points is large, and the values cover a wide range, listing every distinct value individually in a frequency distribution table can still be cumbersome. In such situations, it is more convenient to group the data into class intervals (or classes).
Example: Consider the following data set of marks obtained by 30 students:
| 10 | 20 | 36 | 92 | 95 | 40 | 50 | 56 | 60 | 70 |
| 92 | 88 | 80 | 70 | 72 | 70 | 36 | 40 | 36 | 40 |
| 92 | 40 | 50 | 50 | 56 | 60 | 70 | 60 | 60 | 88 |
Here, the marks range from 10 to 95. Creating a frequency table for each individual mark would be very long. Grouping this data makes sense.
Let's define some terms related to grouped data:
- Class Interval: A range of data values that forms a group. Examples: 0-10, 10-20, 20-30, etc.
- Lower Limit: The smallest value in a class interval (e.g., 10 is the lower limit of the interval 10-20).
- Upper Limit: The largest value in a class interval (e.g., 20 is the upper limit of the interval 10-20).
- Class Size or Width: The difference between the upper limit and the lower limit of a class interval (e.g., for 10-20, the class size is $20 - 10 = 10$).
There are two common methods for forming class intervals:
- Inclusive Method: The upper limit of a class interval is included in that interval. Example: 0-10, 11-20, 21-30. In this method, there are gaps between consecutive intervals.
- Exclusive Method (or Continuous Class Intervals): The upper limit of a class interval is NOT included in that interval, but it is included in the next interval. Example: 0-10, 10-20, 20-30. Here, a value of 10 would be included in the 10-20 interval, not 0-10. This method is preferred for graphical representation like histograms.
Steps to Create a Grouped Frequency Distribution Table:
- Determine the range of the data (difference between the highest and lowest values).
- Decide on a suitable number of class intervals and their class size/width. The intervals should cover the entire range of the data.
- Form the class intervals using either the inclusive or exclusive method, ensuring no data point falls into more than one interval.
- Go through the raw data and use tally marks to count the number of data points that fall into each class interval. In the exclusive method, remember that the upper limit is not included in the interval.
- Count the tally marks for each class interval to get the frequency for that class.
- Sum the frequencies to check if it matches the total number of data points.
Example 2. Group the data from the table provided in Prompt 31 (30 entries) into class intervals 10-20, 20-30, 30-40, and so on, using the exclusive method, and prepare a grouped frequency distribution table.
| 10 | 20 | 36 | 92 | 95 | 40 | 50 | 56 | 60 | 70 |
| 92 | 88 | 80 | 70 | 72 | 70 | 36 | 40 | 36 | 40 |
| 92 | 40 | 50 | 50 | 56 | 60 | 70 | 60 | 60 | 88 |
Answer:
Given raw data: 30 entries of marks.
The class intervals are specified as 10-20, 20-30, etc., using the exclusive method.
Let's list the intervals and count the frequency for each using tally marks. Remember, a value equal to the upper limit goes into the *next* interval.
- 10-20: Includes values from 10 up to (but not including) 20. Data points: 10. Tally: $|$. Frequency: 1.
- 20-30: Includes values from 20 up to (but not including) 30. Data points: 20. Tally: $|$. Frequency: 1.
- 30-40: Includes values from 30 up to (but not including) 40. Data points: 36, 36, 36. Tally: $|||$. Frequency: 3.
- 40-50: Includes values from 40 up to (but not including) 50. Data points: 40, 40, 40, 40. Tally: $||||$. Frequency: 4.
- 50-60: Includes values from 50 up to (but not including) 60. Data points: 50, 50, 50, 56, 56. Tally: $\bcancel{||||}$. Frequency: 5.
- 60-70: Includes values from 60 up to (but not including) 70. Data points: 60, 60, 60, 60. Tally: $||||$. Frequency: 4.
- 70-80: Includes values from 70 up to (but not including) 80. Data points: 70, 70, 70, 70, 72. Tally: $\bcancel{||||}$. Frequency: 5.
- 80-90: Includes values from 80 up to (but not including) 90. Data points: 80, 88, 88. Tally: $|||$. Frequency: 3.
- 90-100: Includes values from 90 up to (but not including) 100. Data points: 92, 95, 92, 92. Tally: $||||$. Frequency: 4.
Construct the grouped frequency distribution table:
| Class Interval | Tally Marks | Frequency |
|---|---|---|
| 10 - 20 | $|$ | 1 |
| 20 - 30 | $|$ | 1 |
| 30 - 40 | $|||$ | 3 |
| 40 - 50 | $||||$ | 4 |
| 50 - 60 | $\bcancel{||||}$ | 5 |
| 60 - 70 | $||||$ | 4 |
| 70 - 80 | $\bcancel{||||}$ | 5 |
| 80 - 90 | $|||$ | 3 |
| 90 - 100 | $||||$ | 4 |
| Total | $1+1+3+4+5+4+5+3+4 = 30$ |
Histograms
We have seen how to organise raw data into a frequency distribution table and how to represent ungrouped data using bar graphs. When data is grouped into class intervals, a special type of bar graph called a histogram is used for its graphical representation. Histograms are particularly useful for visualising the distribution of continuous data.
What is a Histogram?
A histogram is a graphical representation of a grouped frequency distribution where the class intervals are shown on the horizontal axis and the frequencies are shown on the vertical axis. It consists of a series of adjacent rectangles (bars).
Key features of a histogram:
- The base of each rectangle (bar) represents a class interval on the horizontal axis.
- The width of each bar is equal to the class size (or class width) of the interval it represents. If all class intervals have the same size, all bars will have the same width.
- The height of each bar represents the frequency of the corresponding class interval. The height is proportional to the frequency.
- Since the class intervals are continuous (using the exclusive method, like 10-20, 20-30, etc.), there are no gaps between adjacent bars in a histogram. The bars touch each other at the class boundaries.
Histograms show the shape and spread of the data distribution. They help identify where the data is concentrated.
How to Draw a Histogram:
To construct a histogram from a grouped frequency distribution table:
- Draw Axes: Draw the horizontal and vertical axes on a graph sheet.
- Mark Class Intervals on Horizontal Axis: Mark the class intervals along the horizontal axis (x-axis). Start with the lower limit of the first class interval at the origin or after a kink (if the first interval doesn't start at 0). Mark the upper limit of each interval. Ensure that if the class size is uniform, the points on the x-axis marking the intervals are equally spaced.
- Choose a Scale for Vertical Axis: Choose a suitable scale for the vertical axis (y-axis) to represent the frequencies. The scale should accommodate the highest frequency. Label the y-axis as 'Frequency'.
- Draw Rectangular Bars: For each class interval, draw a rectangular bar. The base of the bar lies on the horizontal axis, covering the range of the class interval. The height of the bar is drawn up to the frequency of that class interval on the vertical axis, according to the chosen scale.
- Ensure No Gaps: Draw the bars adjacent to each other. The right edge of one bar coincides with the left edge of the next bar.
- Use Kink/Break (if needed): If the first class interval starts at a value significantly greater than 0, use a zig-zag line (called a kink or break) on the horizontal axis near the origin to indicate that the scale between 0 and the start of the first interval is not shown proportionally.
- Label and Title: Label the horizontal axis appropriately (e.g., 'Height in cm', 'Marks', 'Ages') and give a suitable title to the histogram (e.g., "Histogram showing Distribution of Heights").
Example 1. Draw a histogram for the following grouped frequency distribution table:
| Class Interval | Frequency |
|---|---|
| 10 - 20 | 1 |
| 20 - 30 | 1 |
| 30 - 40 | 3 |
| 40 - 50 | 4 |
| 50 - 60 | 5 |
| 60 - 70 | 4 |
| 70 - 80 | 5 |
| 80 - 90 | 3 |
| 90 - 100 | 4 |
| Total | 30 |
(Assume the data represents marks obtained by students)
Answer:
We are given a grouped frequency distribution table with class intervals and their frequencies. The class intervals are continuous (10-20, 20-30, etc.), and the class size is uniform (100-90 = 10, 90-80 = 10, ... , 20-10 = 10). This is suitable for drawing a histogram.
Construction Steps:
1. Draw the horizontal axis and the vertical axis. Mark their intersection as the origin (0).
2. Mark the class intervals on the horizontal axis. Since the first interval is 10-20, which does not start from 0, draw a kink or zig-zag line on the horizontal axis near the origin.
3. Mark points 10, 20, 30, 40, 50, 60, 70, 80, 90, and 100 on the horizontal axis at equal distances, representing the class boundaries.
4. Label the horizontal axis as 'Marks'.
5. Label the vertical axis as 'Frequency' (Number of Students). Look at the frequencies (1, 1, 3, 4, 5, 4, 5, 3, 4). The highest frequency is 5. Choose a scale for the vertical axis, for example, 1 unit = 1 frequency.
6. Draw rectangular bars for each class interval based on the frequencies:
- For 10-20, height = 1 unit.
- For 20-30, height = 1 unit.
- For 30-40, height = 3 units.
- For 40-50, height = 4 units.
- For 50-60, height = 5 units.
- For 60-70, height = 4 units.
- For 70-80, height = 5 units.
- For 80-90, height = 3 units.
- For 90-100, height = 4 units.
7. Ensure that the bars are drawn adjacent to each other, with no gaps between them.
8. Give the histogram a title: "Histogram Showing Distribution of Marks".
Note: The image file name suggests 'age data', but the table and problem ask for marks. The image will be a representation of a histogram structure with adjacent bars over class intervals and frequency on the vertical axis.
Difference Between a Bar Graph and a Histogram
Although a histogram looks similar to a bar graph, there are fundamental differences between them. The choice between a bar graph and a histogram depends on the type of data you are representing.
| Basis of Difference | Bar Graph | Histogram |
|---|---|---|
| Data Type | It is used to represent categorical or discrete data. Each bar represents a distinct category. | It is used to represent continuous data that is grouped into class intervals. |
| Gaps between Bars | There are gaps between the bars to indicate that the categories are separate and distinct. | There are no gaps between the bars, as they represent a continuous range of data. The bars are adjacent. |
| Horizontal Axis (X-axis) | The x-axis represents distinct categories (e.g., fruits, months, countries). | The x-axis represents a continuous numerical scale divided into class intervals. |
| Bar Width | The width of the bars has no mathematical significance and is chosen for visual clarity. All bars are typically of the same width. | The width of the bars is significant as it represents the class interval. The width can be uniform or variable. |
| Ordering of Bars | The bars can be reordered in any way (e.g., alphabetically, by size) without changing the meaning of the graph. | The bars cannot be reordered, as they are fixed by the numerical sequence of the class intervals on the x-axis. |
Pie Chart
Visual representations of data help us understand information quickly. While bar graphs are excellent for comparing discrete categories or comparing quantities over time, a pie chart is ideal for showing how different parts make up a whole. It's like slicing a pie, where each slice represents a portion of the entire pie.
What is a Pie Chart?
A pie chart, also known as a circle graph, is a circular statistical graph that is divided into sectors (like slices of a pie). Each sector represents a category or component of the data. The entire circle represents the total or the sum of all the components (which corresponds to $100\%$ of the data or $360^\circ$ of the central angle).
The size of each sector in a pie chart is proportional to the value or frequency of the data it represents. This proportionality is determined by the angle of the sector at the center of the circle. A larger share of the total data corresponds to a larger sector with a larger central angle.
Key Idea: Proportionality
The value of a component is proportional to the angle of its sector at the center of the circle.
$\frac{\text{Value of the component}}{\text{Total value}} = \frac{\text{Central angle of the sector}}{360^\circ}$
From this proportionality, we can derive the formula for calculating the central angle for each component:
Central Angle for a Component $= (\frac{\text{Value of the component}}{\text{Total value}}) \times 360^\circ$
... (i)
The sum of all the central angles for all the components must always add up to $360^\circ$ (a full circle).
How to Draw a Pie Chart:
To construct a pie chart, you need the data for different categories and their corresponding values. Follow these steps:
- Calculate Total Value: Sum up the values of all the individual components or categories to find the total value of the data.
- Calculate Central Angles: For each component, calculate the measure of the central angle it should represent using the formula: Central Angle $= (\frac{\text{Value of the component}}{\text{Total value}}) \times 360^\circ$. Ensure that the sum of all calculated central angles is $360^\circ$.
- Draw Circle: Draw a circle of a suitable radius using a compass.
- Draw First Radius: Draw any radius of the circle. This will be the starting line for drawing the first sector.
- Draw Sectors: Starting from the first radius, use a protractor to measure and draw the central angle for the first component. Draw the second radius to complete the first sector. Now, use this second radius as the starting line for the next sector and draw its central angle. Continue this process for all components. The last sector's boundary should align with the first radius drawn.
- Label Sectors: Label each sector clearly with the name of the category it represents. You can also write the value of the component or its percentage of the total within or near the sector.
- Add Title: Give a suitable title to the pie chart that describes the data it represents.
Example 1. The expenditure of a family on various items during a month is given below:
| Item | Expenditure ($\textsf{₹}$) |
|---|---|
| Food | 4000 |
| Clothing | 2000 |
| Education | 1500 |
| Rent | 2500 |
| Savings | 1000 |
Draw a pie chart to represent this data.
Answer:
Calculation of Central Angles:
Step 1: Find the total expenditure.
Total Expenditure $= 4000 + 2000 + 1500 + 2500 + 1000$
$= \textsf{₹}11000$
Step 2: Calculate the central angle for each item using the formula: Central Angle $= (\frac{\text{Expenditure on Item}}{\text{Total Expenditure}}) \times 360^\circ$.
| Item | Expenditure ($\textsf{₹}$) | Fraction of Total | Central Angle Calculation | Central Angle (in degrees) |
|---|---|---|---|---|
| Food | 4000 | $\frac{4000}{11000} = \frac{4}{11}$ | $(\frac{4}{11}) \times 360^\circ$ | $\frac{1440}{11}^\circ \approx 130.91^\circ$ |
| Clothing | 2000 | $\frac{2000}{11000} = \frac{2}{11}$ | $(\frac{2}{11}) \times 360^\circ$ | $\frac{720}{11}^\circ \approx 65.45^\circ$ |
| Education | 1500 | $\frac{1500}{11000} = \frac{15}{110} = \frac{3}{22}$ | $(\frac{3}{22}) \times 360^\circ$ | $\frac{1080}{22}^\circ = \frac{540}{11}^\circ \approx 49.09^\circ$ |
| Rent | 2500 | $\frac{2500}{11000} = \frac{25}{110} = \frac{5}{22}$ | $(\frac{5}{22}) \times 360^\circ$ | $\frac{1800}{22}^\circ = \frac{900}{11}^\circ \approx 81.82^\circ$ |
| Savings | 1000 | $\frac{1000}{11000} = \frac{1}{11}$ | $(\frac{1}{11}) \times 360^\circ$ | $\frac{360}{11}^\circ \approx 32.73^\circ$ |
| Total | 11000 | 1 | Sum of Angles: $\frac{3960}{11}^\circ$ | $360^\circ$ |
Note: Using fractions for calculation and then converting to decimals is often more accurate until the final step of drawing.
Construction Steps:
1. Draw a circle with any convenient radius using compasses.
2. Draw any radius of the circle. This is the starting line for drawing the sectors.
3. Using a protractor, measure the central angle for the first item (Food, approx. $130.9^\circ$) from the drawn radius. Draw the new radius to complete the 'Food' sector.
4. From the end of the previous sector, measure the central angle for the next item (Clothing, approx. $65.5^\circ$) and draw the corresponding sector.
5. Repeat this process for Education (approx. $49.1^\circ$), Rent (approx. $81.8^\circ$), and Savings (approx. $32.7^\circ$).
6. The last sector drawn should finish back at the starting radius. Label each sector with the item name and/or its expenditure value or percentage.
7. Give the pie chart a title: "Distribution of Family Expenditure".
Probability and Related Terms
In our daily lives, we often encounter situations where the outcome is uncertain. For example, when it is cloudy, it might rain or it might not. When you participate in a competition, you might win or lose. Probability is a branch of mathematics that deals with measuring the likelihood of such events occurring. It helps us quantify uncertainty.
Introduction to Probability
Probability provides a numerical measure for the chance of a specific outcome happening in an experiment. The value of probability is always between 0 and 1. A probability of 0 means the event is impossible, while a probability of 1 means the event is certain to happen.
Related Terms in Probability:
To understand probability better, let's define some key terms:
1. Experiment: An operation or activity that produces a set of possible results. The results of an experiment are called outcomes.
Examples of experiments:
- Tossing a coin.
- Rolling a standard six-sided die.
- Drawing a card from a deck of cards.
- Spinning a spinner.
2. Random Experiment: An experiment in which all possible outcomes are known, but the specific outcome of any single trial cannot be predicted in advance. All possible outcomes must have an equal chance of occurring (this is assumed in basic probability).
Examples: Tossing a fair coin, rolling a fair die.
3. Outcome: A single possible result of a random experiment. It is one of the results that can happen when you perform the experiment.
Examples:
- When tossing a coin, 'Head' is an outcome, and 'Tail' is another outcome.
- When rolling a die, '1', '2', '3', '4', '5', '6' are individual outcomes.
4. Sample Space: The set of all possible outcomes of a random experiment. It is usually denoted by the letter 'S'. Listing the sample space helps us identify all the potential results.
Examples:
- Experiment: Tossing a coin. Sample space S = {Head, Tail} or {H, T}. The total number of possible outcomes is 2.
- Experiment: Rolling a standard die. Sample space S = {1, 2, 3, 4, 5, 6}. The total number of possible outcomes is 6.
- Experiment: Tossing two coins. Sample space S = {HH, HT, TH, TT}. The total number of possible outcomes is 4.
5. Event: An event is a collection of one or more outcomes from the sample space of an experiment. It is a subset of the sample space. Events are often denoted by capital letters like E, A, B, etc.
Examples:
- Experiment: Rolling a die (S = {1, 2, 3, 4, 5, 6}).
- Event E1: Getting an even number. The outcomes favorable to this event are {2, 4, 6}. So, E1 = {2, 4, 6}. The number of favourable outcomes for E1 is 3.
- Event E2: Getting a number less than 3. The outcomes favorable to this event are {1, 2}. So, E2 = {1, 2}. The number of favourable outcomes for E2 is 2.
- Event E3: Getting a 5. The outcome favorable to this event is {5}. So, E3 = {5}. The number of favourable outcomes for E3 is 1.
- Experiment: Tossing a coin (S = {H, T}).
- Event E: Getting a head. The outcome favorable to this event is {H}. So, E = {H}. The number of favourable outcomes for E is 1.
Favourable Outcomes: The outcomes that satisfy the condition of a particular event are called the favourable outcomes for that event.
Probability of an Event
The probability of an event E, denoted by P(E), is a numerical measure of how likely the event is to occur. For a random experiment where all outcomes are equally likely, the probability of an event E is defined as the ratio of the number of outcomes favourable to the event to the total number of possible outcomes in the sample space.
Formula for Probability:
P(Event E) $= \frac{\text{Number of outcomes favourable to E}}{\text{Total number of possible outcomes}}$
... (i)
Using symbols, if $n(\text{E})$ is the number of favourable outcomes for event E, and $n(\text{S})$ is the total number of possible outcomes in the sample space S, then:
P(E) $= \frac{n(\text{E})}{n(\text{S})}$
... (ii)
Important Points about Probability:
- Equally Likely Outcomes: The outcomes of an experiment are said to be equally likely if there is no reason to expect one outcome in preference to another. For example, in the toss of a fair coin, 'Head' and 'Tail' are equally likely outcomes. In the roll of a fair die, each of the numbers 1 to 6 is an equally likely outcome.
- The probability of any event E is always a number between 0 and 1, inclusive. $0 \leq \text{P(E)} \leq 1$.
- Impossible Event: An event that can never occur is called an impossible event. The probability of an impossible event is 0. Example: Getting a 7 when rolling a standard die.
- Sure Event (or Certain Event): An event that is certain to occur is called a sure event. The probability of a sure event is 1. Example: Getting a number less than 7 when rolling a standard die.
Understanding a Standard Deck of Cards
Many probability problems involve a standard deck of 52 playing cards. Understanding its composition is crucial.
A standard deck has 52 cards in total. These cards are divided into four suits:
- Spades (♠) and Clubs (♣), which are Black in colour.
- Hearts (♥) and Diamonds (♦), which are Red in colour.
Summary of Suits and Colours:
- Total Cards = 52
- Red Cards = 26 (13 Hearts + 13 Diamonds)
- Black Cards = 26 (13 Spades + 13 Clubs)
Each of the four suits has 13 cards, ranked as follows:
Ace (A), 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack (J), Queen (Q), King (K)
The cards can be further categorised:
- Face Cards (or Picture Cards): These are the cards with faces on them. In each suit, there are 3 face cards: Jack, Queen, and King.
- Total Face Cards = 3 cards/suit × 4 suits = 12 Face Cards.
- (6 Red Face Cards and 6 Black Face Cards)
- Number Cards: These are the cards from 2 to 10. There are 9 number cards in each suit.
- Total Number Cards = 9 cards/suit × 4 suits = 36 Number Cards.
- Aces: There is one Ace in each suit, making a total of 4 Aces.
| Property | Spades (♠) | Clubs (♣) | Hearts (♥) | Diamonds (♦) | Total |
|---|---|---|---|---|---|
| Colour | Black | Black | Red | Red | 26 Black, 26 Red |
| Total Cards per Suit | 13 | 13 | 13 | 13 | 52 |
| Aces | 1 | 1 | 1 | 1 | 4 |
| Number Cards (2-10) | 9 | 9 | 9 | 9 | 36 |
| Face Cards (J, Q, K) | 3 | 3 | 3 | 3 | 12 |
Example 1. A coin is tossed once. What is the probability of getting a head?
Answer:
Experiment: Tossing a coin once.
Sample Space S = {H, T}. Total number of possible outcomes, $n(\text{S}) = 2$.
Event E = Getting a head = {H}. Number of outcomes favourable to E, $n(\text{E}) = 1$.
Using the probability formula:
P(E) $= \frac{n(\text{E})}{n(\text{S})}$
P(Getting a head) $= \frac{1}{2}$
The probability of getting a head is $\frac{1}{2}$.
Example 2. A fair die is rolled once. What is the probability of:
(i) getting a 4?
(ii) getting an even number?
(iii) getting a number greater than 6?
Answer:
Experiment: Rolling a fair die once.
Sample Space S = {1, 2, 3, 4, 5, 6}. Total number of possible outcomes, $n(\text{S}) = 6$.
(i) Event E1 = Getting a 4. The only outcome favourable to E1 is {4}. Number of favourable outcomes, $n(\text{E1}) = 1$.
P(Getting a 4) $= \frac{n(\text{E1})}{n(\text{S})} = \frac{1}{6}$
The probability of getting a 4 is $\frac{1}{6}$.
(ii) Event E2 = Getting an even number. The outcomes favourable to E2 are {2, 4, 6}. Number of favourable outcomes, $n(\text{E2}) = 3$.
P(Getting an even number) $= \frac{n(\text{E2})}{n(\text{S})} = \frac{3}{6}$
Simplify the fraction:
$= \frac{1}{2}$
The probability of getting an even number is $\frac{1}{2}$.
(iii) Event E3 = Getting a number greater than 6. Look at the sample space S = {1, 2, 3, 4, 5, 6}. Are there any outcomes in S that are greater than 6? No. The outcomes favourable to E3 form an empty set {}. Number of favourable outcomes, $n(\text{E3}) = 0$.
P(Getting a number greater than 6) $= \frac{n(\text{E3})}{n(\text{S})} = \frac{0}{6}$
$= 0$
The probability is 0, which indicates that getting a number greater than 6 when rolling a standard die is an impossible event.
Example 3. A bag contains 3 red balls and 5 blue balls. A ball is drawn at random from the bag. What is the probability of getting:
(i) a red ball?
(ii) a blue ball?
Answer:
Experiment: Drawing a ball at random from the bag.
The total number of balls in the bag represents the total number of possible outcomes when drawing one ball.
Total number of balls = Number of red balls + Number of blue balls
$= 3 + 5 = 8$
Total number of possible outcomes, $n(\text{S}) = 8$.
(i) Event E1 = Getting a red ball. The outcomes favourable to E1 are drawing any of the 3 red balls. Number of favourable outcomes, $n(\text{E1}) = 3$.
P(Getting a red ball) $= \frac{n(\text{E1})}{n(\text{S})} = \frac{3}{8}$
The probability of getting a red ball is $\frac{3}{8}$.
(ii) Event E2 = Getting a blue ball. The outcomes favourable to E2 are drawing any of the 5 blue balls. Number of favourable outcomes, $n(\text{E2}) = 5$.
P(Getting a blue ball) $= \frac{n(\text{E2})}{n(\text{S})} = \frac{5}{8}$
The probability of getting a blue ball is $\frac{5}{8}$.
Note: The sum of the probabilities of these two events is P(red ball) + P(blue ball) $= \frac{3}{8} + \frac{5}{8} = \frac{3+5}{8} = \frac{8}{8} = 1$. This makes sense because when drawing a ball, it must be either red or blue (assuming no other colours are present), so these two events cover all possibilities in the sample space.